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Finding Median diagrammatically Marks inclusive series mutation into exclusive series No. of students acaccumulative Frequency (x) (f) (C. M) 410-419 409. 5-419. 5 14 14 420-429 419. 5-429. 5 20 34 430-439 429. 5-439. 5 42 76 440-449 439. 5-449. 5 54 130 450-459 449. 5-459. 5 45 one hundred seventy-five 460-469 459. 5-469. 5 18 193 470-479 469. 5-479. 5 7 cc The normal(a) value of a series may be determinded through the graphic presentation of in micturateation in the form of ogives. This can be done in 2 ways. 1. Presenting the data diagrammatically in the form of slight(prenominal) than ogive or much than ogive . . Presenting the data lifelikely and synchronously in the form of less than and more than ogives. The two ogives be drawn together. 1. slight than nose cone arise Marks Cumulative Frequency (C. M) slight than 419. 5 14 Less than 429. 5 34 Less than 439. 5 76 Less than 449. 5 130 Less than 459. 5 175 Less than 469. 5 193 Less than 479. 5 200 move involve d in calculating median using less than Ogive go up 1. Convert the series into a less than cumulative absolute frequency distribution as shown above . 2. Let N be the total number of students whos data is given.N ordain also be the cumulative frequency of the last interval. Find the (N/2)th particular proposition(student) and look into it on the y-axis. In this case the (N/2)thitem (student) is 200/2 = 100thstudent. 3. drive a vertical from 100 to the sort forth to hack on the Ogive shorten at accuse A. 4. From point A where the Ogive curve is cut, draw a perpendicular on the x-axis. The point at which it touches the x-axis willing be the median value of the series as shown in the graph. The median turns out to be 443. 94. 2. more than Ogive burn down to a greater extent than marks Cumulative Frequency (C. M) more than than 409. 5 200 More than 419. 5 186 More than 429. 166 More than 439. 5 124 More than 449. 5 70 More than 459. 5 25 More than 469. 5 7 More than 47 9. 5 0 move involved in calculating median using more than Ogive approach 1. Convert the series into a more than cumulative frequency distribution as shown above . 2. Let N be the total number of students whos data is given. N will also be the cumulative frequency of the last interval. Find the (N/2)thitem(student) and mark it on the y-axis. In this case the (N/2)thitem (student) is 200/2 = 100thstudent. 3. limn a perpendicular from 100 to the right to cut the Ogive curve at point A. . From point A where the Ogive curve is cut, draw a perpendicular on the x-axis. The point at which it touches the x-axis will be the median value of the series as shown in the graph. The median turns out to be 443. 94. 3. Less than and more than Ogive approach Another way of graphical determination of median is through simultaneous graphic presentation of both the less than and more than Ogives. 1. Mark the point A where the Ogive curves cut each other. 2. Draw a perpendicular from A on the x-axis. The corresponding value on the x-axis would be the median value.